Alok is attending a workshop 'How to do more with less and today's theme is Working with fewer digits. The speakers discuss how a lot of miraculous mathematics can be achieved if mankind (as well as womankind) had only worked with fewer digits. The problem posed at the end of the workshop is 'How many 5 digit numbers can be formed using the digits 1, 2, 3, 4, 5 (but with repetition) that are divisible by 4?' Can you help Alok find the answer?

A. 100
B. 125
C. 75
D. 85


The chances for last two digits:{(1,2);(2,4);(3,2);(4,4)[because with repetition];(5,2)} there are totally five chances

The chances for 1st and 2nd digit chances same 5 digits (1,2,3,4,5) because with repetition then the probaility of 1st two digit is=5*5

Then the total probability =(5*5)*(5)=125

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