Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 31, the number of points equidistant from all the 3 lines is

A. 3
B. 4
C. 0
D. 1


The answer is option B.
There are 4 such points. One point is the incenter of the triangle.
3 are the excenters with respect to each angle of the triangle. In the picture given,
below I is the Incenter and JA, JB, JC are excenters.


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